Typescript array of objects with minimum set keys

Issue

I want to filter an array, but only filter based on 2 keys (name & surname OR n & s) out of any possible number of unknown keys

const items = [
   { ..., "n": "John", "s": "Doe" }, // keep - n & s keys are valid
   { ..., "name": "John", "surname": "Doe" }, // keep - name & surname keys are valid
   { ..., "n": "John", "surname": "Doe" }, // remove - n & surname keys are invalid
]

const result = filterValids(items); 
// [
//   { "n": "John", "s": "Doe", ... }, // seen as valid
//   { "name": "John", "surname": "Doe", ...}, // seen as valid
// ]

My solution below does not work

function filterValids(items: (AtLeastOne<shortKeys, longKeys>)[]) {
  const filtered: typeof items | [] = [];
  for (const item of items) {
      const name = item.n || item.name; // name does not exist on `AtLeastOne<shortKeys, longKeys>
      const surname = item.s || item.surname; // surname does not exist on `AtLeastOne<shortKeys, longKeys>`

      if (checkValidity({name, surname}))
        filtered.push(item) // `AtLeastOne<shortKeys, longKeys>` is not assignable to parameter of type `never`
  }

  return filtered
}

type AtLeastOne<T, U = { [K in keyof T]: Pick<T, K> }> = Partial<T> & U[keyof U];

type longKeys = {
  name: string,
  surname: string
}

type shortKeys = {
  n: string,
  s: string
}

Solution

I have found the solution by using ((shortKeys | longKeys) & { [key: string]: any })[]

const items = [
   { "someKey": "someValue",    "n": "John",     "s": "Doe"       }, // keep - n & s keys are valid
   { "someKey2": "someValue2",  "name": "John",  "surname": "Doe" }, // keep - name & surname keys are valid
   { "someKey3": "someValue3",  "n": "John",     "surname": "Doe" }, // remove - n & surname keys are invalid
]

const result = filterValids(items); 
// [
//   { "n": "John", "s": "Doe", ... }, // seen as valid
//   { "name": "John", "surname": "Doe", ...}, // seen as valid
// ]

Solution

function filterValids(items: ((shortKeys | longKeys) & { [key: string]: any })[]) {
  const filtered = [];
  for (const item of items) {
      const name = item.n || item.name; 
      const surname = item.s || item.surname; 

      if (checkValidity({name, surname}))
        filtered.push(item) // 
  }

  return filtered
}

type longKeys = {
  name: string,
  surname: string
}

type shortKeys = {
  n: string,
  s: string
}

Answered By - Kevin Potgieter