Issue
To display multiple lines in html body, simple codes:
websites = ["https://www.reddit.com/","https://en.wikipedia.org/","https://www.facebook.com/"]
html = """
<!DOCTYPE html>
<html>
<body>
<h1>Hi, friend</h1>
<p>$websites!</p>
</body>
</html>
"""
html = Template(html).safe_substitute(websites = "<p>".join(websites))
Now I want to change the links to hyperlinks with friendly names.
names = ["News", "Info", "Media"]
Changed the line to:
<p><a href=$websites>$names</a></p>
and:
html = Template(html).safe_substitute(websites = "<p>".join(websites),
names= "<p>".join(names))
What I want in the html to show is:
But it doesn't show properly. What's the right way to do that?
Solution
Don't do '<p>'.join(websites). This will create a string by joining all the elements of a list and stick the '<p>' between them.
so that gives you "https://www.reddit.com/<p>https://en.wikipedia.org/"<p>https://www.facebook.com/" which is not what you want (I don't think It's valid as well).
You don't have any <a> link tags. So you need to Create those.
The href will point to the website and inside the <a> tag you have the name you want to appear
<a href={link}>{link_name}</a>
This is what you want to do:
websites = ["https://www.reddit.com/","https://en.wikipedia.org/","https://www.facebook.com/"]
html = """
<!DOCTYPE html>
<html>
<body>
<p>$websites</p>
</body>
</html>
"""
tag_names = ['News', 'Info', 'Media']
a_links = '<br/>'.join([f'<a href={link}>{link_name}</a>' for link, link_name in zip(websites, tag_names)])
html = Template(html).safe_substitute(websites=a_links)
Answered By - masonCherry
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