Issue
I want to do something like this:
var promise = IAmAEmptyPromise;
if(condition){
promise = ApiService.getRealPromise();
}
promise.then(function(){
//do something
});
So I want to declare a promise, which can be resolved using then. However this promise may be overwritten by another promise, which returns content. Later I want to resolve the promise whether it has content or not. Is this possible? I tried with:
var promise = $q.defer().promise;
if(!$scope.user){
promise = UserService.create(params);
}
promise.then(function(){
//either user was created or the user already exists.
});
However this does not work when a user is present. Any ideas?
Solution
Like Bixi wrote, you could use $q.when()
which wraps a promise or a value into a promise. If what you pass to when()
is a promise, that will get returned, otherwise a new promise is created which is resolved directly with the value you passed in. Something like this:
var promise;
if(!$scope.user){
promise = UserService.create(params);
} else {
promise = $q.when($scope.user);
}
promise.then(function(user){
//either user was created or the user already exists.
});
Answered By - Anders Ekdahl
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