Function that returns all the elements where field is 1

Issue

I have the array:

var tabs = [
    {"id": 1, "Name": "Top", "Paris": 1, "London": 1, "Rome": 1},
    {"id": 2, "Name": "Best", "Paris": 1, "London": 0, "Rome": 0},
    {"id": 3, "Name": "Cheap", "Paris": 0, "London": 1, "Rome": 0}
];

How can I write a function that receives as argument one of the towns (London or Paris or Rome) different each time and returns the elements of the array which the argument is 1? For example, I want to take all the elements where London=1.

Solution

var tabs= [

{ "id": 1, "Name": "Top","Paris":1,"London":1, "Rome":1},
{ "id": 2, "Name": "Best","Paris":1,"London":0,"Rome":0},
{ "id": 3, "Name": "Cheap","Paris":0,"London":1,"Rome":0}

];

var getElementsWith=function(array,name){
  var myElements=[];
  array.forEach(function(tab){
    if(tab[name]===1)
      myElements.push(tab);
  });
  return myElements;
  };

console.log(getElementsWith(tabs,"Paris")); 

Answered By - Mr.Bruno