Issue
Is it possible to define a CSS style for an element, that is only applied if the matching element contains a specific element (as the direct child item)?
I think this is best explained using an example.
Note: I'm trying to style the parent element, depending on what child elements it contains.
<style>
/* note this is invalid syntax. I'm using the non-existing
":containing" pseudo-class to show what I want to achieve. */
div:containing div.a { border: solid 3px red; }
div:containing div.b { border: solid 3px blue; }
</style>
<!-- the following div should have a red border because
if contains a div with class="a" -->
<div>
<div class="a"></div>
</div>
<!-- the following div should have a blue border -->
<div>
<div class="b"></div>
</div>
Note 2: I know I can achieve this using javascript, but I just wondered whether this is possible using some unknown (to me) CSS features.
Solution
As far as I'm aware, styling a parent element based on the child element is not an available feature of CSS. You'll likely need scripting for this.
It'd be wonderful if you could do something like div[div.a]
or div:containing[div.a]
as you said, but this isn't possible.
You may want to consider looking at jQuery. Its selectors work very well with 'containing' types. You can select the div, based on its child contents and then apply a CSS class to the parent all in one line.
If you use jQuery, something along the lines of this would may work (untested but the theory is there):
$('div:has(div.a)').css('border', '1px solid red');
or
$('div:has(div.a)').addClass('redBorder');
combined with a CSS class:
.redBorder
{
border: 1px solid red;
}
Here's the documentation for the jQuery "has" selector.
Answered By - KP.
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