typescript get values of Promise.allSettled

Issue

I want to get values of Promise allSettled result in typescript code. In JavaScript this work well.

  Promise.allSettled([
      Promise.resolve(33),
      new Promise(resolve => setTimeout(() => resolve(1000), 0)),
      25000,
      Promise.reject(new Error('failed!'))
    ])
    .then(values => {
      let allValues = values.filter(c=>c.status === 'fulfilled').map(v=>v.value);
      console.log(allValues);
    });

But in typescript I can't find correct syntax. the item just have status and has no value property. I am using the latest version of typescript 3.9.7

Solution

Ok I finally found the correct syntax for using Promise.allSettled in typescript:

Update: Thanks to @myol I updated the code without unnecessary map:

const dummyResolve1 =  Promise.resolve(1000);
const dummyResolve2 = new Promise(resolve => setTimeout(() => resolve(2000), 0));
const dummyError = Promise.reject(new Error('failed'));
const dummyPromises = [dummyResolve1, dummyResolve1, dummyError];

Promise.allSettled(dummyPromises)
  .then(results => {
    const allValues = (results.filter(c=>c.status === 'fulfilled') as PromiseFulfilledResult<any>[])
    .map(c=>c.value);

    console.log(allValues);

    const failedResults = 
    (results.filter(c=>c.status === 'rejected') as PromiseRejectedResult[])
    .map(c=>c.reason);
    
    console.log(failedResults);
});

Old code:

Promise.allSettled([
  Promise.resolve(1000),
  new Promise(resolve => setTimeout(() => resolve(2000), 0)),
  1500,
  Promise.reject(new Error('failed'))
])
.then(values => {
  let allValues = values.filter(c=>c.status === 'fulfilled').map(c=> <PromiseFulfilledResult<any>>c).map(c=>c.value);
  console.log(allValues);
  let failedResults =  values.filter(c=>c.status === 'rejected').map(c=> <PromiseRejectedResult>c).map(c=>c.reason);
  console.log(failedResults);
});

Answered By - Hamed Mahdizadeh