Issue
I want to force a function of a specific type, but want to have a default value for some functions.
And I tried with simple code like below
type MyFunc = (str: string) => number;
const myAFunc: MyFunc = (str) => Number(str);
const myBFunc: MyFunc = (str = '9999') => Number(str);
myAFunc('a');
myAFunc(); // wants to occur error
myBFunc('b');
myBFunc(); // wants to NOT occur error
But it's not working.
Is there some way to solve it?
Solution
A and B func has different types, don't force them into same type:
type MyAFunc = (str: string) => number;
type MyBFunc = (str?: string) => number;
const myAFunc: MyAFunc = (str) => Number(str);
const myBFunc: MyBFunc = (str = '9999') => Number(str);
myAFunc('a');
myAFunc(); // wants to occur error
myBFunc('b');
myBFunc(); // wants to NOT occur error
Answered By - gaborp
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