Issue
AgGrid expects node(s) to be passed in to lot of it's data functions. How do you get a node by index? Look at the snip below:
api.forEachNode(function(node){
api.refreshRows([node]);
})
I can pass the node
parameter to refreshRows()
function since I'm getting it through forEachNode()
.
How do you get a node by index without iterating through forEachNode()
?
Solution
You can use getVirtualRow()
method to get a single row. This function is a part of the Row Model. You can get the Row Model by getModel()
function.
var model = api.getModel();
console.log(model.getVirtualRow(idx));
Answered By - Charlie
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